Puvodni tabulka: 0 1 2 3 4 5 6 7 8 9 a b c d e f 0 06060707070706070606070707070607 1 06060707070706070606070707070607 2 06060407070706070606020707070607 3 06060707070706070606070707070607 4 06060406070606060606020607060606 5 06060406070606060606020607060606 6 06060406070606060606020607060606 7 06060406070606060606020607060606 8 06060407070706070606020707070607 9 06060707070706070606070707070607 a 06060707070706070606070707070607 b 06060707070706070606070707070607 c 06060406060606060606020606060606 d 06060406060606060606020606060606 e 06060406060606060606020606060606 f 06060406060606060606020606060606 A8 je tvale LOW tak tabulku na pulku a pro prehlednost zrusim 0 0 1 2 3 4 5 6 7 8 9 a b c d e f 0 6 6 7 7 7 7 6 7 6 6 7 7 7 7 6 7 1 6 6 7 7 7 7 6 7 6 6 7 7 7 7 6 7 2 6 6 4 7 7 7 6 7 6 6 2 7 7 7 6 7 3 6 6 7 7 7 7 6 7 6 6 7 7 7 7 6 7 4 6 6 4 6 7 6 6 6 6 6 2 6 7 6 6 6 5 6 6 4 6 7 6 6 6 6 6 2 6 7 6 6 6 6 6 6 4 6 7 6 6 6 6 6 2 6 7 6 6 6 7 6 6 4 6 7 6 6 6 6 6 2 6 7 6 6 6 A4 je signal A12 urcuje ktera polovina pameti EPROM je aktivni - muzeme zase odstranit pulku tabulky 0 1 2 3 4 5 6 7 0 6 6 7 7 7 7 6 7 1 6 6 7 7 7 7 6 7 2 6 6 4 7 7 7 6 7 3 6 6 7 7 7 7 6 7 4 6 6 4 6 7 6 6 6 5 6 6 4 6 7 6 6 6 6 6 6 4 6 7 6 6 6 7 6 6 4 6 7 6 6 6 Pro prehlednost zmenim obsah tabulky na x - 6 - /CSromx=1, CAS=0 nic neni aktivni r - 7 - /CSromx=1, CAS=1 aktivni ram e - 4 - /CSromx=0, CAS=0 aktivni rom a muzeme uz zlepsit popisky podle signalu adresace cpu read (A3)= 0 0 0 0 1 1 1 1 cpu write (A2)= 0 0 1 1 0 0 1 1 video (A1)= 0 1 0 1 0 1 0 1 --------------- a13*a14*a15=0 pc4=0 pc5=0 x x r r r r x r a13*a14*a15=1 pc4=0 pc5=0 x x r r r r x r a13*a14*a15=0 pc4=1 pc5=0 x x e r r r x r a13*a14*a15=1 pc4=1 pc5=0 x x r r r r x r a13*a14*a15=0 pc4=0 pc5=1 x x e x r x x x a13*a14*a15=1 pc4=0 pc5=1 x x e x r x x x a13*a14*a15=0 pc4=0 pc5=1 x x e x r x x x a13*a14*a15=1 pc4=0 pc5=1 x x e x r x x x No a tady je uz videt ze pro pc5=1 a video=1 neni aktivni ram